Question

# In a concave mirror experiment, an object is placed at a distance $$x_1$$ from the focus and the image is formed at a distance $$x_2$$ from the focus. The focal length of the mirror would be :

A
x1x2
B
x1x2
C
x1+x22
D
x1x2

Solution

## The correct option is C $$\dfrac{x_1+x_2}{2}$$Given $$u=(f+x_{1})$$ and $$v=(f+x_{2})$$The focal length $$f=\dfrac{uv}{u+v}=\dfrac{(f+x_{1})(f+x_{2})}{(f+x_{1})+(f+x_{2})}$$On solving, we get $$f^{2}=x_{1}x_{2}$$ or $$f=\sqrt{x_{1}x_{2}}$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More