In a conductor, electrons drift from lower to higher potential. If drift speed is $V_{d}$ and speed due to random motion (due to temperature) is $V_{r}$ , then net velocity of electron can be.

V_{d} + V_{r}

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V_{r} - V_{d}

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\sqrt{V_{d}^{2} + V_{r}^{2}}

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All of the above

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Solution

The correct option is D All of the above
$V_{n e t} =_{d} +_{r}$

$V_{m a x} = V_{d} + V_{r}$
$V_{m i n} = V_{r} - V_{d}$ , and if angle between $_{d}$ & $_{r}$ is $90^{\circ}$ then, $V = \sqrt{V_{d}^{2} + V_{r}^{2}}$

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