In a constant volume calorimeter, $3.5 g$ of a gas with molar mass $28$ was burnt in excess oxygen at $298 K$ . The temperature of the calorimeter was found to increase from $298.0 K$ to $298.45 K$ . If the heat capacity of the calorimeter is $2.5 k J / K$ , the numerical value of the heat of combustion of the gas in kJ/ mol is ________.

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Solution

Energy release at constant volume due to combustion of 3.5gm of gas $= 2.5 \times 0.45$
Hence energy released due to the combustion of 28gm(1 mole) of gas $= 2.5 \times 0.45 \times \frac{28}{3.5} = 9 k J / m o l$

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Energy release at constant volume due to combustion of 3.5gm of gas=2.5×0.45Hence energy released due to the combustion of 28gm(1 mole) of gas =2.5×0.45×283.5=9 kJ/mol

Energy release at constant volume due to combustion of 3.5gm of gas $= 2.5 \times 0.45$
Hence energy released due to the combustion of 28gm(1 mole) of gas $= 2.5 \times 0.45 \times \frac{28}{3.5} = 9 k J / m o l$