Question

In a copper voltameter, the mass deposited in 30s in m gram. If the current time graph is as shown in the fig., the e.c.e. of copper, in gm/coul, will be

• A. m
• B. $\frac{m}{2}$
• C. 0.06 m
• D. 0.1 m

Answer 1

The correct option is B $\frac{m}{2}$

From graph, $AB=10$ s $AP=0.1$ A $OC=30$ s

Area of trapezium(OABC) $=\frac{1}{2}\times [AB+OC]\times AP=\frac{1}{2}\times [10+30]\times 0.1=2$

$\therefore$ Electrochemical equivalent of copper $Z=\frac{m}{Area}=\frac{m}{2}$ gm/coulomb