In a copper voltmeter containing copper sulphate solution, a current of $1 a m p e r e$ is passed for $1 h o u r$ . Taking the E.C.E. of copper as $0.000329 g / C$ , the weight of copper deposited is approximately

6 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.2 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.12 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0329 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1.2 g$
$m$ $=$ $Z i t$ $=$ $3.3$ $\times 10^{- 4} \times 1 \times 3600 g$
$=$ $3.3$ $\times 3.6 \times 10^{- 1} g$
since, $π^{2} = 10$ the product of $3.3$ and $3.6$ must be a little greater than $10$ . As per the given options one of the possible values of this product must be $12$ .
so, $m$ $=$ $12 \times 10^{- 1}$ $=$ $1.2 g$

Suggest Corrections

Similar questions

When an electric current is passed through a solution containing copper sulphate, copper gets deposited on which electrode?

When current is passed through Copper Sulphate solution, Copper sulphate dissociates into copper and sulphate.This free copper deposits on one of the electrodes.What about the loss of copper in the solution?

Q. An electric current is passed through silver nitrate solution using silver electrodes.

15.28

g of silver was found to be deposited on cathode. What will be the weight of copper deposited on cathode if same amount of electricity is passed through copper sulphate solution using copper electrodes?

Q. When

96500

coulomb of electricity is passed through a copper sulphate solution, the amount of copper deposited will be:

Q. A current of 1.5 A flows through a copper voltameter. The thickness of copper deposited on the electrode surface of area 50cm in 20 minutes will be

(

Density of copper

= 9000

kg/m

^{3}

and e.c.e. of copper

=

0.00033 g/C

)

Join BYJU'S Learning Program

In a copper voltmeter containing copper sulphate solution, a current of 1ampere is passed for 1hour. Taking the E.C.E. of copper as 0.000329g/C, the weight of copper deposited is approximately

The correct option is B 1.2gm=Zit=3.3×10−4×1×3600g =3.3×3.6×10−1gsince,π2=10 the product of 3.3 and 3.6 must be a little greater than 10. As per the given options one of the possible values of this product must be 12.so, m=12×10−1=1.2g

In a copper voltmeter containing copper sulphate solution, a current of $1 a m p e r e$ is passed for $1 h o u r$ . Taking the E.C.E. of copper as $0.000329 g / C$ , the weight of copper deposited is approximately