Question

In a cricket match five batsman $A,B,C,D$ and $E$ scored an average of $36$ runs. $D$ scored $5$ more than $E;E$ scored $8$ fewer than $A;B$ scored as many as $D$ and $E$ combined; and $B$ and $C$ scored $107$ between them. How many runs did $E$ score?

• A. $62$
• B. $45$
• C. $28$
• D. $20$

Answer 1

Answer: (D)

$20$

Average of $ABCDE=36runs$.
Sum of runs of $ABCDE=36\times 5=180$
$D=5+E,E=A-8$, so $A=E+8,B=D+E$, so $B=5+2E$
$B+C=107$, so $C=107-5-2E=102-2E$, so $A+B+C+D+E=180$
Now, put the values of $ABCDE$
$E+8+5+2E+102-2E+5+E+E=180$
So $E=20$.