Question

In a cricket match Hari hits $12$ 'sixes' out of $48$ balls he faced. It a ball is selected at random, what is the probability that he would have not hit a "six" for that ball?

Answer 1

Total number of balls Hari faced $=48$.
Let $E$ be the event of hitting sixes, then the number of favourable events $=12$.
Then probability of the event of hitting six is $P\left(E\right)=\frac{12}{48}=\frac{1}{4}$.
We know that the probability of a certain (sure) event is $1$.
Therefore, the probability that he would not have hit a six is
$P\left(E^{\prime }\right)=1-P\left(E\right)=1-\frac{1}{4}=\frac{3}{4}$.