Question

In a cricket match, the bowler bowls at an average speed of 144 km/hr. The ball travels a distance of 12 m before bouncing. After bouncing, it travels 5 m more with same speed before reaching the batsman. Find the time taken by the ball to reach the batsman after being released from the bowler’s hand.

• A. 17/144 s
• B. 17/40 s
• C. 5/40 s
• D. 12/40 s

Answer 1

The correct option is B

17/40 s

Average bowling speed of the bowler = 144 km/hr

1km = 1000m

1 hr = 60 min = 60 $\times$ 60 seconds= 3600 s

144 km/hr = 144 $\times$ $\frac{1000m}{3600s}$

=144 $\times$ $\frac{10}{36}$ m/s

= 40 m/s

Total distance travelled by the ball = 12m + 5m = 17m

Average speed$=\frac{Totaldistancetravelled}{Totaltimetaken}$

40 m/s = $\frac{17}{Totaltimetaken}$

Total time taken=$\frac{17}{40}s$