Question

In a cross between individuals homozygous for (a, b) and wild type($++$). In this cross $700$ out of $1000$ individuals were of parental type. Then the distance between a and b is?

• A. $70$ map unit
• B. $35$ map unit
• C. $30$ map unit
• D. $15$ map unit

Answer 1

The correct option is C $30$ map unit

In this cross, 700/1000 i.e. 70% of individuals are of the parental type. This means that rest 30% individuals are recombinant types. Since recommendation frequency in percentage is equal to the distance in map unit between genes, hence the distance between a and b is 30 map unit.

So, the correct option is '30 map unit'.