Question

In a cross between individuals hormozygous for $(a,b)$ and wild type $(++)700$ out of $1000$ individuals were of parental type. Then the distance between $a$ and $b$ is

• A. 70 map unit
• B. 35 map unit
• C. 30 map unit
• D. 15 map unit

Answer 1

Answer: (C)

30 map unit

700 out of 1000 individuals are parental types which mean 300 are recombinants. Hence, recombination frequency here is 30%. As the distance between the genes (map units) is equal to the percentage of crossing-over events that occurs between different alleles, the distance between 'a' and 'b' is 30 map unit.

So, the correct option is '30 map unit'.