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Question

In a crystalline solid, anions B are arranged in ccp lattice and cations A occupy 50% of the octahedral voids and 50% of the tetrahedral voids. What is the formula of the solid?

A
AB
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B
A3B2
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C
A2B2
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D
A2B4
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Solution

The correct option is B A3B2
No of atoms in a CCP unit cell=similar to FCC=4
Therefore no of B atoms present=4
No of A atom=tetrahedral void and octohedral void(4+2)=6
The formula of the compound = A3B2

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