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Question

In a cubic close-packed structure of mixed oxides, the lattice is made up of oxide ions, one-tenth of the tetrahedral voids are occupied by divalent (X2+) ions, while one-half of the octahedral voids are occupied by trivalent ions (Y3+), then formula of the oxide is:

A
XY4O4
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B
X2YO4
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C
X2Y5O10
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D
X5Y4O10
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Solution

The correct option is B X2Y5O10
Oxygen forms the CCP (fcc) lattice.
ZO2=4

Effective number of X2+=110× Tetrahedral voids =110×8=45

Effective number of Y3+=12× Octahedral voids =12×4=2

Formula X45Y2O4=X25YO2=X2Y5O10

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