In a cubic structure of a crystal which is made from X and Y, where X atoms are at the corners of the cube and Y at the face centres of the cube. The molecular formula of the compound is :

X_{2} Y

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X_{2} Y

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X Y_{2}

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X Y_{3}

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Solution

The correct option is D $X Y_{3}$
$X Y_{3}$
Explanation :
Number of A atoms per unit cell $= 8 \times \frac{1}{8} = 1$
Number of B atoms per unit cell $= 6 \times \frac{1}{2} = 3$
Composition of solid $= A B_{3}$

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In a cubic structure of a crystal which is made from X and Y, where X atoms are at the corners of the cube and Y at the face centres of the cube. The molecular formula of the compound is :

The correct option is D XY3XY3 Explanation : Number of A atoms per unit cell =8×18=1 Number of B atoms per unit cell =6×12=3 Composition of solid =AB3

The correct option is D $X Y_{3}$
$X Y_{3}$
Explanation :
Number of A atoms per unit cell $= 8 \times \frac{1}{8} = 1$
Number of B atoms per unit cell $= 6 \times \frac{1}{2} = 3$
Composition of solid $= A B_{3}$