Question

In a current source inverter shown below,
if source current $\left(I_s\right)=10A$ , then the rms value of fundamental output current is

• A. 7 A
• B. 8.5 A
• C. 9 A
• D. 9.5 A

Answer 1

The correct option is C 9 A

The Fourier expression for load current is,
$I_0={\sum }_{n=1,3,\mathrm{5..}}^{\infty }\frac{4I_s}{n\pi }\sin n{\omega }_{0}t$
$I_{01\left(rms\right)}=\frac{4I_s}{\sqrt{2}\pi }=\frac{4\times 10}{\sqrt{2}\pi }=9A$