Question

In a cutting test with 0.3 mm flank wear as tool failure criterion, a tool life of 10 min was obtained at a cutting velocity of 20 m/min. Taking tool life exponent as $0.25$, the tool life in minutes at 40 m/min of cutting velocity will be

• A. $0.506$
• B. $0.625$
• C. $3.140$
• D. $5.002$

Answer 1

The correct option is B $0.625$

$n=0.25,T_1=10min,V_1=20m/min$
If $V_2=40m/min$
Taylor's tool life equation:
$V_1{T}_1^n=V_2{T}_2^n$
$T_2=T_1{\left(\frac{V_1}{V_2}\right)}^{1/n}=10{\left(\frac{20}{40}\right)}^{1/0.25}$
$=10{\left(\frac{1}{2}\right)}^4=0.625min$