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Standard XII

Physics

Heat Pumps

In a cyclic h...

Question

In a cyclic heat engine operating between a source temperature of $600^{0} C$ and a sink temperature of $20^{0} C$ , the least rate of heat rejection per kW net output of the engine is,

0.505kW

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0.490kW

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0.333kW

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none of the above

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Solution

The correct option is A 0.505kW
$∴ H e a t a b s o r p t i o n = \frac{T_{1} - T_{2}}{T_{1}}$

$= \frac{873 - 293}{873} = 0.664$

$∴ H e a t R e j e c t e d = 1 - h e a t a b s o r b e d$
$= 1 - 0.664$
$∴ H e a t r e j e c t e d = 0.335$
Hence the heat of rejection per kW is $0.335$

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In a cyclic heat engine operating between a source temperature of 6000C and a sink temperature of 200C, the least rate of heat rejection per kW net output of the engine is,

The correct option is A 0.505kW∴Heatabsorption=T1−T2T1=873−293873=0.664∴HeatRejected=1−heatabsorbed=1−0.664∴Heatrejected=0.335Hence the heat of rejection per kW is 0.335

In a cyclic heat engine operating between a source temperature of $600^{0} C$ and a sink temperature of $20^{0} C$ , the least rate of heat rejection per kW net output of the engine is,

The correct option is A 0.505kW
$∴ H e a t a b s o r p t i o n = \frac{T_{1} - T_{2}}{T_{1}}$

$= \frac{873 - 293}{873} = 0.664$

$∴ H e a t R e j e c t e d = 1 - h e a t a b s o r b e d$
$= 1 - 0.664$
$∴ H e a t r e j e c t e d = 0.335$
Hence the heat of rejection per kW is $0.335$