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Thermodynamic Processes

In a cyclic p...

Question

In a cyclic process $Δ Q = 0$ .

A

True

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B

False

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Solution

The correct option is B False
The First Law of Thermodynamics states that energy can be converted from one form to another with the interaction of heat, work and internal energy, but it cannot be created nor destroyed, under any circumstances. Mathematically, this is represented as
$Q = Δ U + W$
with,
$Q$ is the heat exchanged between a system and its surroundings,
$Δ U$ is the total change in internal energy of a system,
$W$ is the work done by or on the system.
For a cyclic process, change in internal energy is zero. $Q$ = $W$ .

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Similar questions

Δ U_{1}

Δ U_{2}

be the change in internal energy in process A and B respectively,

Δ Q

be the net heat given to the system in process (A+B) and

Δ W

be the net work done by the system in the process (A+ B).
i)

Δ U_{1} + Δ U_{2} = 0

Δ U_{1} - Δ U_{2} = 0

Δ Q + Δ W = 0

Δ Q + Δ W = 0

Q. Refer to figure. Let ∆U₁ and ∆U₂ be the change in internal energy in processes A and B respectively, ∆Q be the net heat given to the system in process A + B and ∆W be the net work done by the system in the process A + B.

(a) ∆U₁ + ∆U₂ = 0.
(b) ∆U₁ − ∆U₂ = 0.
(c) ∆Q − ∆W = 0.
(d) ∆Q + ∆W = 0

Q. Match the thermodynamic processes taking place in a system with the correct conditions.
In the table,

Δ Q

is the heat supplied,

Δ W

is the work done and

Δ U

is the change in internal energy of the system.

Process	Condition
(i) Adiabatic	(A) $Δ W = 0$
(ii) Isothermal	(B) $Δ Q = 0$
(iii) Isochoric	(C) $Δ U \neq 0$ , $Δ W \neq 0$ , $Δ Q \neq 0$
(iv) Isobaric	(D) $Δ U = 0$

X = -5 can this be expressed as a linear equation in two variables?

True

False

Q. Two angles can have exactly five points in common.

True
False

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