Question

In a cyclic process, heat transfers are $+34.7kJ$ , $-15.2kJ$, $-13.56kJ$ and $+21.5kJ$. What is the net work done in the process?

• A. $+17.44kJ$
• B. $+27.44kJ$
• C. $-17.44kJ$
• D. $-27.44kJ$

Answer 1

The correct option is D $-27.44kJ$

In the cyclic process, $△U_{cyc}=0$ as internal energy is state function.
as $w+q=△U$
Therefore, $w_{cyc}+q_{cyc}=0$
$w_{cyc}=-q_{cyc}$
so, the net work done is
$w_{cyc}=-[34.7-15.2-13.56+21.5]kJ$
$w_{cyc}=-27.44kJ$