Question

In a cyclic process shown on the P-V diagram, the magnitude of the work done is

• A. $\pi {\left(\frac{P_2-P_1}{2}\right)}^2$
• B. $\pi {\left(\frac{V_2-V_1}{2}\right)}^2$
• C. $\frac{\pi }{4}(P_2-P_1)(V_2-V_1)$
• D. $\pi (P_2{V}_2-P_1{V}_1)$

Answer 1

The correct option is C $\frac{\pi }{4}(P_2-P_1)(V_2-V_1)$

The correct answer is option(C).

As work done in cyclic process = area of closed path.