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Question

In a cyclic quadrilateral ABCD,it is being given that A=(x+y+10),B=(y+20),C=(x+y30), and D=(x+y),Then B=?(a)70     (b)80   (c)100   (d)110


Solution

here
A+C=180
B+D=180
x+y+10+x+y-30=180
2x+2y-20=180
x+y=100
​​​​​
y+20+x+y=180
x+2y=160------------1
x+y=100-------------2

1-2
y=60

so angle B=y+20=80

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