In a cyclotron, a charged particle(1) Speeds up inside a dee because of magnetic field(2) Gains kinetic energy between the dees because of electric field (3)Undergoes acceleration all time(4) Both (2) and (3)

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Q. An alternating electric field, of frequency

ν

, is applied across the Dees

(

radius

= R)

of a cyclotron that is being used to accelerate protons

(

mass

= m,

charge

= e)

. The operating magnetic field

(B)

used in the cyclotron and the kinetic energy

(K)

of the proton beam, produced by it, are given by

Q. An alternating electric field, of frequency v, is applied across the dees (radius

=

R) of a cyclotron that is being used to accelerate protons (mass

=

m). The operating magnetic field (B) used in the cyclotron and the kinetic energy (K) of the proton beam, produced by it, are given by

Q. In a cyclotron, magnetic field of

1.4 W b / m^{2}

is used. To accelerate protons, how rapidly should the electric field between the Dees he reversed?
(

π = 3.142, M p = 1.67 \times 10^{- 27} k g, e = 1.6 \times 10^{- 19} C

)

(a) Draw a schematic sketch of a cyclotron. Explain clearly the role of crossed electric and magnetic field in accelerating the charge. Hence derive the expression for the kinetic energy acquired by the particles.
(b) An $α$ -particle and a photon are released from the centre of the cyclotron and made to accelerate.
(i) Can both be accelerated at the same cyclotron frequency ? Give reason to justify your answer.
(ii) When they are accelerated in turn, which of the two will have higher velocity at the exit slit of the dees ?

Q. A particle of charge q, mass m and velocity v moves in a circular path inside the dees of a cyclotron. If the magnetic field exerted on the particle is B, calculate the radius R of the particles path.

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