Question

In a cyclotron, magnetic field of $1.4Wb/m^2$ is used. To accelerate protons, how rapidly should the electric field between the Dees he reversed?
($\pi =3.142,Mp=1.67\times {10}^{-27}kg,e=1.6\times {10}^{-19}C$)

Answer 1

The double of frequency is how rapidly should the electric field between the Dees be reversed per second.

$f=\frac{qB}{2\pi m}=\frac{1.6\times {10}^{-19}\times 1.4}{2\times 3.14\times 1.67\times {10}^{-27}}=213\times {10}^{5}Hz$

electric field between the Dees should be reversed $426\times {10}^5$ times in a second.