In a cylinder, 2.0moles of an ideal monatomic gas initially at 1.0×106Pa and 300K expands until its volume doubles. The work done if the expansion is isobaric is
A
4980J
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B
2800J
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C
2300J
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D
4630J
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Solution
The correct option is A4980J Work done in isobaric process=ΔW=PΔV=nRΔT Here, n=no. of moles=2 At constant pressure, volume doubles⇒ temperature doubles ⇒ΔT=To=300K Thus,ΔW=2×8.3×300J=4980J