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Question

In a cylinder , 2 mole of an ideal gas at temperature 300k undergoes isothermal expansion until its volume double. Work done by the gas is loge2=0.693)

A
1875J
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B
2695J
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C
3457J
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D
4485J
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Solution

The correct option is C 3457J
In isothermal expansion, T is constant
PV=nRT=constant
P1V1=P2V2=K, P=KV
Workdone=Pdv=KVdc
=klogev2v1=kloge2vv=kloge2
Also, k=nRT=2×R×300=600R
Work done=600Rloge2=3456.9612
=3.456 kJ.

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