GivenThe internal radius of vessel r=14cm
Volume of the vessel 30800cm3
Let the height of the vessel be h.
∴πr2h=30800cm3
⇒227×14×14×h=30800⇒h=30800×714×14×22
=50cm
∴ The internal surface area of cylindrical vessel
2πrh=2×227×14×50=4400cm2
Hence the internal curved surface area of cylindrical vessel =4400cm2