In a ΔABC, if ∠A = 60°, ∠B = 80° and the bisectors of ∠B and ∠C meet at O, then ∠BOC =

(a) 60°

(b) 120°

(c) 150°

(d) 30°

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Solution

In the given ΔABC,and . Bisectors of and meet at O.

We need to find

Since, OB is the bisector of.

Thus,

Now, using the angle sum property of the triangle

In ΔABC, we get,

Similarly, in ΔBOC

Hence,

Therefore, the correct option is (b).

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Similar questions

In a $Δ A B C,$ if $∠ A = 60^{\circ}, ∠ B = 80^{\circ}$ and the bisectors of $∠ B$ and $∠ C$ meet at $O$ , then $∠ B O C =$ ___

△ A B C

∠ A = 60^{o}

∠ B = 80^{o}

∠ B

∠ C

O

∠ C

∠ B O C

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