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Question

In a ΔABC, a=1, c=2 and A is given. If b1,b2 are two values of b such that 2b2=b1 then sinA=

A
58
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B
516
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C
532
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D
316
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Solution

The correct option is A 532
A is given
a=1
c=2
cosA=b2+c2a22bc
b22bccosA+c2a2=0 (Quadratic in b)
Roots are b1 & b2 (Given 2b2=b1)
b1+b2=3b2=2ccosA sum of roots
b1b2=2b22=c2a2 product of roots
2b22=2212
b22=32
b2=32
3b2=2ccosA
332=2(2)cosA
cosA=3342
sinA=1cos2A
=12732
sinA=532.

1191662_1195535_ans_02d80749aebb43709d58d724f1349ee0.jpg

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