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Question

In a ΔABC,a(b cosC c cos B) is equal to -

A
b + c
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B
b - c
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C
b2c2
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D
b2+c2
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Solution

The correct option is C b2c2
We know from cosine rule
cosC=a2+b2C22ab
cosB=a2+c2b22ac
So we'll use these in the given expression.
a{b(a2+b2c22ab)c(a2+c2b22ac)}
a2+b2c2a2c2+b22
=2(b2c2)2
=b2c2

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