In a ΔABC, AB=AC and the length of the altitude from A to BC is h. The area and perimeter of ΔABC is A and P respectively. The circumradius of ΔABC is r. The value of 1rlimh→0AP3 is
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Solution
In ΔBOD, BD2=r2−(h−r)2⇒BD=√2hr−h2
In ΔBAD, AB2=h2+(2hr−h2)⇒AC=AB=√2hr