In a $Δ A B C, A D$ is the bisector of $∠ A,$ meeting side $B C$ at $D$ .
If $A B = 3.5 c m,$ $A C = 4.2 c m$ and $D C = 2.8 c m$ ,
Find $B D$ .

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Solution

According to angle bisector theorem,
$\frac{A B}{B D} = \frac{A C}{D C}$ .
$B D = \frac{A B \times D C}{A C} = \frac{3.5 \times 2.3}{4.2} = 2.33 c m$ .

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