Question

In a $\Delta$ABC, $\angle$B = 90${}^0$ and the longest side is 5 cm more than the middle side and the middle side is 5 cm more than the shortest one. Find the shortest side.

• A. 20 cm
• B. 15 cm
• C. 25 cm
• D. 35 cm

Answer 1

The correct option is B

15 cm

Let the length of the smaller side be `x', then the length of the other two sides will be x-5 and x+5. (x + 5)${}^2$ = x${}^2$ + (x-5)${}^2$ $\Rightarrow$ x = 20 cm Smaller side = 15 cm