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Question

In aΔABC,if3A=4B=6C then A:B:C=?

(a) 3:4:6 (b) 4:3:2 (c) 2:3:4 (d) 6:4:3

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Solution

ANSWER:
LCM of 3, 4 and 6 = 12
3 A=4B=6C
(Given)
Dividing throughout by 12, we get
3 A/12=4/B12=6C/12A/4=B/3=C/2
Let A/4=B/3=C/2=k, where k is some constant
Then, A=4k,B=3k,C=2k
A:B:C = 4 k : 3 k : 2 k = 4 : 3 : 2
Hence, the correct answer is option (b).


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