In a - ABC- if a -5- b -6 and C -60- show that its area is 15 -3-2 sq- units-

The area of a triangle ABC is given by Δ=1/2ab sin C =1/2× 5× 6 sin 60^∘ =15√(3)/2 sq.unit. ...

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Standard XII

Mathematics

Area Using Sine Rule

In a Δ ABC, i...

Question

$I n a Δ A B C, i f a = 5, b = 6 a n d C = 60^{\circ}, show that its area is \frac{15 \sqrt{3}}{2} s q . u n i t s .$

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Solution

$The area of a triangle ABC is given by Δ = \frac{1}{2} a b s i n C = \frac{1}{2} \times 5 \times 6 s i n 60^{\circ} = \frac{15 \sqrt{3}}{2} s q . u n i t .$

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In a ΔABC, if a=5, b=6 and C=60∘, show that its area is 15√32sq. units.

The area of a triangle ABC is given byΔ=12ab sin C=12×5×6 sin 60∘=15√32 sq.unit.

$I n a Δ A B C, i f a = 5, b = 6 a n d C = 60^{\circ}, show that its area is \frac{15 \sqrt{3}}{2} s q . u n i t s .$

$The area of a triangle ABC is given by Δ = \frac{1}{2} a b s i n C = \frac{1}{2} \times 5 \times 6 s i n 60^{\circ} = \frac{15 \sqrt{3}}{2} s q . u n i t .$