In a - ABC- if a -5- b -6 and C -60- show that its area is 15 -3-2 sq- units-

The area of a triangle ABC is given by Δ=1/2ab sin C =1/2× 5× 6 sin 60^∘ =15√(3)/2 sq.unit. ...

480

You visited us 480 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Area Using Sine Rule

In a Δ ABC, i...

Question

$I n a Δ A B C, i f a = 5, b = 6 a n d C = 60^{\circ}, show that its area is \frac{15 \sqrt{3}}{2} s q . u n i t s .$

Open in App

Solution

$The area of a triangle ABC is given by Δ = \frac{1}{2} a b s i n C = \frac{1}{2} \times 5 \times 6 s i n 60^{\circ} = \frac{15 \sqrt{3}}{2} s q . u n i t .$

Suggest Corrections

Similar questions

Q. In

∆ A B C, if a = 5, b = 6 and C = 60 °

, show that its area is

\frac{15 \sqrt{3}}{2} sq

. units.

$I n a Δ A B C, i f a = \sqrt{2}, b = \sqrt{3} a n d c = \sqrt{5}, show that its area is \frac{1}{2} \sqrt{6} s q . u n i t s .$

Q. In

∆ A B C, if a = \sqrt{2}, b = \sqrt{3} and c = \sqrt{5}

, show that its area is

\frac{1}{2} \sqrt{6} sq .

units.

Q. Area of the triangle ABC a=2, b= 5,

∠ C = 60

in sq. units is

In a right triangle $Δ A B C$ with right angle at B and BD is a perpendicular dropped onto the hypotenuse. If AC = 2AB, what is the area of $Δ A B D$ ? (area of $Δ A B C$ = 5 sq units.)

Join BYJU'S Learning Program

In a ΔABC, if a=5, b=6 and C=60∘, show that its area is 15√32sq. units.

The area of a triangle ABC is given byΔ=12ab sin C=12×5×6 sin 60∘=15√32 sq.unit.

$I n a Δ A B C, i f a = 5, b = 6 a n d C = 60^{\circ}, show that its area is \frac{15 \sqrt{3}}{2} s q . u n i t s .$

$The area of a triangle ABC is given by Δ = \frac{1}{2} a b s i n C = \frac{1}{2} \times 5 \times 6 s i n 60^{\circ} = \frac{15 \sqrt{3}}{2} s q . u n i t .$