Question

In a $\Delta$ ABC, if $A{B}^2=B{C}^2+A{C}^2,$ then the right angle is at:

• A. A
• B. B
• C. C
• D. None of these

Answer 1

The correct option is C C

By Pythagora's theorem,
$(hypotenuse{)}^2=(perpendicular{)}^2+(base{)}^2$
Clearly, $AB$ is hypotenuse$,$ $BC$ and $AC$ are either base or perpendicular.
Since$,$ $AB$ is hypotenuse$,$ therefore neither $A$ nor $B$ is right angle.
Therefore, $C$ is right angle.