CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a ΔABC, if AB+BC=10cm,BC+CA=12cm,CA+AB=16cm, then the perimeter of the Δ is

A
19cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
17cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
38cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 19cm
AB+AC=16cm ....(1)
AB+BC=10cm ...(2)
AC+BC=12cm ...(3)
Adding eq(1), (2), and (3), we get
2(AB+AC+BC)=38cm
AB+AC+BC=19cm
Perimeter of triangle is 19cm.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Congruence of Triangles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon