Question

In a $\Delta ABC$ if $\angle 3a=\angle 4b=\angle 6c$ find the angles$.$

Answer 1

Given$,\Delta ABC$
In which $3a=4b=6c$
Sum of all angles in a triangle $=180°$

Therefore,
$3a+4b+6c=180$
$3a+3a+3a=180$
$9a=180$
$a=180/9$
$a=20$
$=3a$
$=3\left(20\right)$
$=60$
$3a=4b=6c=60$

Hence, this is the answer.