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Question

In a ΔABC if 3a=4b=6c find the angles.

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Solution

Given,ΔABC
In which 3a=4b=6c
Sum of all angles in a triangle =180°

Therefore,
3a+4b+6c=180
3a+3a+3a=180
9a=180
a=180/9
a=20
=3a
=3(20)
=60
3a=4b=6c=60

Hence, this is the answer.

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