In a - ABC- if b2-a2-c2 then B is -

The correct option is D π/2 From Pythagoras theorem b^2=a^2+c^2 i.e., AC^2=BC^2+AB^2 ∠ B=90^o . ...

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In a Δ ABC,...

Question

In a $Δ A B C,$ if $b^{2} = a^{2} + c^{2}$ then B is :

[\frac{π}{4}, \frac{π}{2}]

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Acute

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Obtuse

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\frac{π}{2}

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If in a $△ A B C, a^{2} c o s^{2} A = b^{2} + c^{2}$ then

△ A B C

∠ C = \frac{π}{2}

sin (A - B) = \frac{a^{2} - b^{2}}{a^{2} + b^{2}}

Δ A B C

a^{2}, b^{2}, c^{2}

cot A, cot B, cot C

△ A B C,

(\frac{a^{2} + b^{2}}{a^{2} - b^{2}}) sin (A - B) = 1

C

cos (A - B) = tan (\frac{C}{2} - \frac{π}{4})

Δ A B C, a^{2} - b^{2} - c^{2} = 0

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