In a ΔABC,R= circumradius and r= inradius. Then the value of acosA+bcosB+ccosCa+b+c is?
In a Δ ABC, R = circumradius and r = inradius. The value of acosA+bcosB+ccosCa+b+c is equal to
In a Δ ABC, let ∠ C = π/2 .If r is the inradius and R is the circumradius of the triangle, then 2 (r +R) is equal to