Question

In a $\Delta$ ABC, right angled at A, if AB = 5, AC = 12 and BC 13, find sin B, cos C and tan B.

Answer 1

With reference to $\angle B$, we have
Base = AB = 5, Perpendicular = AC = 12 and,
Hypotenuse = BC = 13
$\therefore sinB=\frac{AC}{BC}=\frac{12}{13}$
and, $tanB=\frac{AC}{AB}=\frac{12}{5}$
With reference to $\angle C$, we have
Base = AC = 12, Perpendicular = AB = 5 and, Hypotenuse = BC = 13
$\therefore cosC=\frac{AC}{BC}=\frac{12}{13}$