In a ΔABC,right angled at B, AB=24 cm, BC=7 cm. Determine
(i) sin A, cos A
(ii) sin C, cos C
In ΔABC, right angled at B. AB = 24 cm, BC = 7 cm. Determine:
(i) sin A cos A,
(ii) sin C, cos C.
Let AB = 24 cm
BC = 7cm Using Pythagoras theorem, we have
AC2=AB2+BC2=(24cm)2+(7cm)2=576cm2+49cm2=625cm2
So, AC = 25 cm
Now,
(i) sin A = BCAC=725(ii) cos A = ABAC=2425(iii) sin C = ABAC=2425(iv) cos C = BCAC=725