Question

In a $\Delta$ ABC right angled at C, find $\sin A\cos B+\cos A\sin B$.

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

The correct option is A $1$

we have, $\sin A\cos B+\cos A\sin B$

$=\sin (A+B)$

$=\sin (\pi -c)$

$=\sin (\pi -\frac{\pi }{2})$

$=\sin \left(\frac{\pi }{2}\right)$

$=1$.