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Question

In a Δ ABC right angled at C, find sinAcosB+cosAsinB.

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is A 1
we have, sinAcosB+cosAsinB

=sin(A+B)

=sin(πc)

=sin(ππ2)

=sin(π2)

=1.

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