In a ΔABC, the internal bisector of ∠A meets opposite side BC at D. Through vertex C, line CE is drawn parallel to DA which meets BA produced at point E. Which of the following is true?
ΔACE is isosceles
Given: AD∥EC,
∠BAD=∠DAC
∠BAD=∠AEC [Corresponding angles] ..... (1)
∠DAC=∠ACE [Alternate angles] ..... (2)
And we know that ∠BAD=∠DAC,
So, ∠AEC=∠ACE
⇒ΔAEC is isosceles triangle.