In a ΔABC, the sides AB,BC and CA are 10 cm,8 cm and 7 cm respectively. On AB, a point P is taken such that AP=4 cm. If PQ is drawn parallel to BC, then its length is equal to:
Since PQ∥BC, APPB=AQQC ...Basic Proportionality Theorem
In △APQ and △ABC
∠A is common angle.
∠APQ=∠ABC ....Corresponding angles since PQ||BC
∴△APQ∼△ABC ....AA test of similarity
APAB=AQAC=PQBC ....C.S.S.T
410=PQ8.........(On substituting the values)
PQ=3.2cm.