In a device I=40μA[eV/VT−1] where VT=0.025V. Find the dynamic resistance when V=0.5V
A
zero
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B
8Ω
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C
10Ω
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D
30Ω
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E
none of these
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Solution
The correct option is A zero Current is given as I=IS[eV/VT−1] where IS=40μA Thus differentiating it w.r.t V, we get dIdV=ISVTeV/VT or we get dynamic resistance R=dVdI=VTISeV/VT=0.02540×10−6[e20] ∴R=0.02540×10−6×5×108≈0Ω