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In a didybrid...

Question

In a didybrid cross between RRYY and rryy, the number of RrYy $F_{2}$ genotypes will be

A

4

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B

3

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C

2

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D

9

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Solution

The correct option is A
4

It’s a di-hybrid test cross, so the ratio is 1 : 1 : 1 : 1. The progeny with RrYy genoype is selfed to get the $F_{2}$ generation. Then 4 RrYygenotypes are obtained in $F_{2}$ generation.

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