In a dihybrid cross between AABB and aabb, the ratio of AABB, AABb, aaBb and aabb in F $_{2}$ generation is

9:3:3:1

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1:1:1:1

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1:2:2:1

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1:1:2:2

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Solution

The correct option is C 1:2:2:1
P generation: AABB x aabb
F $_{1}$ generation: AaBb
Selfing of F $_{1}$ generation: AaBb x AaBb
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Hence, from the following table we can count the different genotypes as:
AABB = 1
AABb = 2
aaBb = 2
aabb = 1
Thus, the correct answer is option C.

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