Question

In a diode AM detector, the output circuit consists of $R=1k\Omega$ and $C=pF$. A carrier signal of 100 k Hz is to be detected. Is it good?

• A. Yes
• B. No
• C. Information is not sufficient
• D. None of the above

Answer 1

Answer: (B)

No

For better demodulation
$\frac{1}{f_c}<<RC$
Here, $\frac{1}{f_c}=\frac{1}{100\times {10}^3}={10}^{-5}s$
and $RC={10}^3\times 10\times {10}^{-12}={10}^{-8}s$
So, $\frac{1}{f_c}$ is not less than RC. Hence, it is not good.