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V-I Characteristics for a P-N Junction Diode

In a diode va...

Question

In a diode valve the plate currents are $I_{1}$ and $I_{2}$ at plate voltage 400 $V$ and 200 $V$ respectively, at constant filament current. The ratio $I_{1} / I_{2}$ is :

A

\frac{1}{2 \sqrt{2}}

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B

\frac{1}{2}

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C

2

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D

4

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Solution

The correct option is C $2$
Here, the resistance will remain unchanged. Therefore, the ratio $\frac{I_{1}}{I_{2}}$ is equal to $\frac{V_{1}}{V_{2}}$ .
So, $\frac{I_{1}}{I_{2}} = \frac{V_{1}}{V_{2}} = \frac{400 Volt}{200 Volt} = 2$

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