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Question

In a direct shear test, the shear stress and normal stress on a dry sand sample at failure are 0.6 kg/cm2 and 1 kg/cm2 respectively. The angle of internal friction of the sand will be nearly.

A
25o
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B
31o
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C
37o
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D
43o
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Solution

The correct option is B 31o
τ=σ tan Φ;tan Φ=0.61=0.6
tan 30o=13=0.577
as tan Φ>tan 30o
Φ>30o;ϕ=31o

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