In a direct shear test, the shear stress and normal stress on a dry sand sample at failure are 0.6kg/cm2 and 1kg/cm2 respectively. The angle of internal friction of the sand will be nearly.
A
25o
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B
31o
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C
37o
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D
43o
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Solution
The correct option is B31o τ=σtanΦ;tanΦ=0.61=0.6 tan30o=1√3=0.577 astanΦ>tan30o ∴Φ>30o;ϕ=31o